posted by Kate on .
(x-2)^2 / 49 + (y+1)^2 / 25 = 1
a.) what are the vertices?
b.) What are the major and minor axises?
I always have troubling understanding how to find these. :(
Any help is greatly appreciated!
for x^2/a^2 + y^2/b^2 = 1,
semi-major axes are a and b. Select the larger for major, smaller for minor.
so, here major=14, minor=10
foci are on the major axis, at distance c from center, where a^2 = b^2 + c^2
so, c = √(49-25) = √24 = 2√6
Knowing the distances, and the center, and the direction of the major axis, you can easily write the coordinates of the foci and vertices.
Thank you, @Steve !
Would you happen to know how to find the Foci for this equation?!?!