posted by Lucy on .
on a day when the air temperature is 34 degrees celsius, a can of soft drink is taken from the fridge at a temperature of 4 degrees celsius at 2pm. Thereafter the temperature of the can satisfies the differential equation; dT/dt=0.1(34-T), where t is the number of minutes after 2pm. What is the temperature of the can at 2:15pm? At what time does the temperature reach 30 degrees?
dT/(34-T) = 0.1dt
Integrate both sides
t=0, T=4 => 4=34-C => C=30
A) Substitute t=15 to solve for T.
B) Substitute T=30 to solve for t.
wow thank you so much