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October 20, 2014

October 20, 2014

Posted by **Lucy** on Thursday, May 24, 2012 at 4:53am.

- Math -
**MathMate**, Thursday, May 24, 2012 at 8:04amdT/dt=0.1(34-T)

dT/(34-T) = 0.1dt

Integrate both sides

-ln(34-T)=0.1t+c

34-T=Ce^(-0.1t)

T=34-Ce^(-0.1t)

Initial conditions:

t=0, T=4 => 4=34-C => C=30

so

T=34-30e^(0.1t)

A) Substitute t=15 to solve for T.

B) Substitute T=30 to solve for t.

- Math -
**Lucy**, Thursday, May 24, 2012 at 8:05amwow thank you so much

- Math :) -
**MathMate**, Thursday, May 24, 2012 at 8:49amYou're welcome!

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