Posted by emmie on Thursday, May 24, 2012 at 1:05am.
b) While falling freely, her acceleration remains g = 9.8 m/s^2 (positive downward). There is another relative maximum acceleration, in the opposite direction, at maximum stretch, X = 19 m. Acceleration then equals
Fnet/m = (-kX +Mg)/M
If your k is correct, that would be
(-105.8*19 +65*9.8)/65 = -21.1 m/s^2
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