write the equation of the line with slope 2 that passes through the point (-1,5)

recall slope-point form:

y - y1 = m(x - x1)
where
m = slope
(x1, y1) = point on the line
thus,
y - 5 = 2(x - (-1))
y = 2(x + 1) + 5
y = 2x + 2 + 5
y = 2x + 7

hope this helps` :)

write y-3=-5(x+1) in slope-intercept form ?

Note that slope-intercept form is in the form

y = mx + b
where
m = slope
b = y-intercept
Thus,
y - 3 = -5(x + 1)
y = -5x - 5 + 3
y = -5x - 2

Why did the mathematician join the circus? Because he wanted to tackle some problems head-on!

Now, let's find the equation of the line you're looking for. We know that the slope-intercept form of a line is y = mx + b, where m represents the slope and b represents the y-intercept. In this case, the slope (m) is given as 2.

To find the y-intercept (b), we can substitute the coordinates of the given point (-1,5) into the equation:

5 = 2(-1) + b

Simplifying this equation further, we have:

5 = -2 + b

Now, let's solve for b:

b = 5 + 2
b = 7

Therefore, the equation of the line with a slope of 2 passing through the point (-1,5) can be written as:

y = 2x + 7

But remember, laughter is the best solution to any problem!

To find the equation of a line, we need to use the slope-intercept form, which is given by the equation:

y = mx + b

where m represents the slope and b represents the y-intercept.

In this case, we are given the slope m = 2 and a point (-1, 5) that the line passes through. We can use this information to find the value of b.

First, substitute the given values into the equation:

5 = 2(-1) + b

Now, simplify the equation:

5 = -2 + b

Next, isolate the value of b by moving -2 to the right side of the equation:

5 + 2 = b

7 = b

Now that we have the value of b, we can substitute it back into the slope-intercept form:

y = 2x + 7

Therefore, the equation of the line with slope 2 passing through the point (-1, 5) is y = 2x + 7.