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July 22, 2014

July 22, 2014

Posted by **Janae** on Wednesday, May 23, 2012 at 11:22pm.

- Math -
**Jai**, Wednesday, May 23, 2012 at 11:35pmrecall slope-point form:

y - y1 = m(x - x1)

where

m = slope

(x1, y1) = point on the line

thus,

y - 5 = 2(x - (-1))

y = 2(x + 1) + 5

y = 2x + 2 + 5

y = 2x + 7

hope this helps` :)

- Math -
**Janae**, Wednesday, May 23, 2012 at 11:38pmwrite y-3=-5(x+1) in slope-intercept form ?

- Math -
**Jai**, Wednesday, May 23, 2012 at 11:40pmNote that slope-intercept form is in the form

y = mx + b

where

m = slope

b = y-intercept

Thus,

y - 3 = -5(x + 1)

y = -5x - 5 + 3

y = -5x - 2

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