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Posted by on Wednesday, May 23, 2012 at 11:22pm.

write the equation of the line with slope 2 that passes through the point (-1,5)

  • Math - , Wednesday, May 23, 2012 at 11:35pm

    recall slope-point form:
    y - y1 = m(x - x1)
    where
    m = slope
    (x1, y1) = point on the line
    thus,
    y - 5 = 2(x - (-1))
    y = 2(x + 1) + 5
    y = 2x + 2 + 5
    y = 2x + 7

    hope this helps` :)

  • Math - , Wednesday, May 23, 2012 at 11:38pm

    write y-3=-5(x+1) in slope-intercept form ?

  • Math - , Wednesday, May 23, 2012 at 11:40pm

    Note that slope-intercept form is in the form
    y = mx + b
    where
    m = slope
    b = y-intercept
    Thus,
    y - 3 = -5(x + 1)
    y = -5x - 5 + 3
    y = -5x - 2

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