Posted by emmie on Wednesday, May 23, 2012 at 10:22pm.
When fully stretched X = 19 m beyond the unstretched length, the stored potential energy (k/2)*19^2 in the cord equals the gravitational potential energy loss, (M*g*30 m). Therefore,
k/2 = M*g*30/(19)^2 = 52.9
k = 105.8 N/m
i got that answer but for part b i got 9.8 is that right ?
No, there is a larger negative acceleration at maximum stretch. I am sorry I overlooked the second part of your question. Look for my answer in a later post.
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