Posted by **john** on Wednesday, May 23, 2012 at 9:53pm.

How many kilograms of NH3 are needed to produce 2.90 x 10^5 kg of (NH4)2SO4?

- science -
**Jai**, Wednesday, May 23, 2012 at 11:12pm
first, write the chemical reaction:

NH3 + H2SO4 -> (NH4)2SO4

then we balance this:

2NH3 + H2SO4 -> (NH4)2SO4

then we find the weight of NH3 and (NH4)2SO4. We can do this by getting each atomic mass of the element in the chemical formula, and add them. It can be found on periodic table of elements.

NH3 = 17 kg/kmol

(NH4)2SO4 = 132 kg/kmol

then, we get the number of moles of the product by dividing the given by the mass:

2.90*10^5 kg (NH4)2SO4 / 132 kg/kmol = 2196.97 kmol (NH4)2SO4

then we get the number of moles of NH3 required (stoichiometric ratios from the balanced equation):

2196.97 kmol (NH4)2SO4 * (2 kmol NH3 / 1 kmol (NH4)2SO4) = 4393.93 kmol NH3

finally, we multiply this by the mass of NH3 to get the total mass required:

4393.93 kmol NH3 * (17 kg/kmol) = 74696.97 kg NH3

hope this helps~ :)

## Answer This Question

## Related Questions

- Chemistry - how many kilograms of NH3 are needed to produce 2.90x10^5kg of (NH4)...
- Chemistry - how many kilograms of NH3 are needed to produce 2.90x10^5kg of (NH4)...
- science - How many kilograms of NH3 are needed to produce 1.00 x 10^5 kg of (NH4...
- CHEMISTRY - HOW MANY MOLES OF NH3 WOULD BE FORMED FROM 50 GRAMS OF (NH4)2SO4 IN ...
- Chemistry - Rank the following fertilizers in decreasing order of mass ...
- chem - How do you balance this equation?: (NH4)2SO4+Ca(OH)2==>CaSO4+NH3+H20 ...
- Physical science - What is the formula of magnesium sulfate and ammonia? My work...
- Chemistry - How do I balance CuSO4 + NH3 + H2O = (NH4)2SO4 + Cu(NH3)4(OH)2 Thank...
- chemistry-Buffer Q - You have a solution of .5 L of 1.74g of NH3 and 4.15g of (...
- chemistry - the question reads: a) balance the equation: H3PO4 + Ca(OH)2 --> ...

More Related Questions