Posted by Hannah on Wednesday, May 23, 2012 at 9:32pm.
You can try a proportional one-sample z-test for this one since this problem is using proportions.
Using a formula for a proportional one-sample z-test with your data included, we have:
z = .24 - .20 -->test value (120/500 is .24) minus population value (.20) divided by
√[(.20)(.80)/500] --> .80 represents 1-.20 and 500 is sample size.
Finish the calculation. Remember if the null is not rejected, then there is no difference. If the null is rejected, then p > .20.
I hope this will help.
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