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Measurement and Conversion
Energy
Calorie conversion
356 Cal to kilowatt-hours
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a)339 Cal to kilowatt-hours
Top answer:
It is important to distinguish Calories (with a capital C) from gram-calories. 339 Cal = 339,000 cal
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On a typical night at a restaurant, the patio lights use 210.8 kilowatt-hours of electricity and the courtyard lights use h
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B. 210.8 + h
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On a typical night at a restaurant, the patio lights use 206.31 kilowatt-hours of electricity and the courtyard lights use h
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Yes, you can be correct sometimes! Thank you for double-checking. The correct answer is indeed D.
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Question The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours. The use of electricity in the US in 1950 was
Top answer:
(6.3×10^9) + (4.3×10^11) = 4.363×10^11
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The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours.
The use of electricity in the US in 1950 was 4.3 x 10^11
Top answer:
No, the equation to find the total kilowatt-hours of electricity used during these two years is not
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On a typical night at a restaurant, the patio lights use 204.77 kilowatt-hours of electricity and the courtyard lights use h
Top answer:
D. 204.77 + h
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Power companies typically bill customers based on the number of kilowatt-hours used during a single billing period. A kilowatt
Top answer:
well, you could choose a left Riemann sum or a right Riemann sum or an in between Riemann sum. For
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Power companies typically bill customers based on the number of kilowatt-hours used during a single billing period. A kilowatt
Top answer:
B. 24*30 = 720 hours so the energy used is ∫[0,720] P(t) dt A. You can approximate that using n
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The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours. The use of electricity in the US in 1950 was 4.3 x
Top answer:
The correct response is: (6.3×10^9) + (4.3×10^11) = 4.363 × 10^11. The total kilowatt-hours of
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The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours.
The use of electricity in the US in 1950 was 4.3 x 10^11
Top answer:
None of the responses provided are correct. To find the total kilowatt-hours of electricity used
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Related Questions
The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours.
The use of electricity in the US in 1950 was 4.3 x 10^11
How many calories are required to heat 25.0 g of platinum from 24.5 °C to 75°C (specific heat of platinum = 0.139 J/gK)?
1. 47
The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours.
The use of electricity in the US in 1950 was 4.3 x 10^11
The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours. The use of electricity in the US in 1950 was 4.3 x
The use of eletricty in the US in 1902 was 6.03 times 10^9 kilowatt-hours.
The use of eletricty in the US in 1950 was 4.3 times
the use of electricity in the US in 1902 was 6.03x10^9 kilowatt-hours
the use of electricity in the US in 1950 was 4.3x10^11
The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours.
The use of electricity in the US in 1950 was 4.3 x 10^11
The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours.
The use of electricity in the US in 1950 was 4.3 x 10^11
The use of electricity in the US in 1902 was 6.03 x 10^9 kilowatt-hours.
The use of electricity in the US in 1950 was 4.3 x 10^11
The use of eletricty in the US in 1902 was 6.03 times 10^9 kilowatt-hours.
The use of eletricty in the US in 1950 was 4.3 times