Posted by Adam on Wednesday, May 23, 2012 at 11:45am.
If I visulize the situation,
mg*sintheta=mv^2/r.
Now if the pole movement is small, then r= length*sinTheta
mg(sinTheta)=mv^2/length*sinTheta
v= sinTheta*sqrt (g*lengthrope)
that is what you have in theequation, but not what you calculated. Recalculate
Sorry I keep recalculating, but i keep getting 4.36 m/s and thats wrong I don't know what I am doing wrong.
sqrt(g*lengthrope)=4.64
sin70deg=hmmmm.
Ok, without a picture, I am not certain of where the angle is.
If the angle is measured from the downward vertical to the slanted rope, then sin70 is correct.
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