given triangle ABC with side b=14 ft, c=17 ft, and a=17 ft, find the measure of angle A.
Use the law of cosines.
a^2 = b^2 + c^2 -2bc cosA
cosA = (b^2 +c^2-a^2)/(2bc)
= 0.4118
A = 65.7 degrees
a^2 = b^2 + c^2 -2bc cosA
cosA = (b^2 +c^2-a^2)/(2bc)
= 0.4118
A = 65.7 degrees