what are the rectangular coordinates of
(-2(pi/6))?
please help.
???
Is that a polar coordinate point?
is there a missing comma?
did you mean (-2 , π/6) ?
look at the solution I gave here to a similar problem
http://www.jiskha.com/display.cgi?id=1267493976
yes. sorry. I forgot the comma
To find the rectangular coordinates of a point given in polar coordinates, you can use the following formulas:
x = r * cos(theta)
y = r * sin(theta)
In this case, the polar coordinate given is (-2(pi/6)). Let's break it down:
The value before the parentheses, -2, represents the radius (r). The negative sign indicates that the point is on the opposite side of the origin.
The value inside the parentheses, (pi/6), represents the angle in radians (θ). In this case, it is pi/6.
Now, let's plug these values into the formulas:
x = -2 * cos(pi/6)
y = -2 * sin(pi/6)
To evaluate the trigonometric functions, we can use the special angles in the unit circle.
cos(pi/6) = √3/2
sin(pi/6) = 1/2
So, substituting these values into the formulas:
x = -2 * (√3/2) = -√3
y = -2 * (1/2) = -1
Therefore, the rectangular coordinates of (-2(pi/6)) are (-√3, -1).