What is the molarity of the solution produced when 14.1 grams of ammonia is dissolved in sufficient water to prepare .100 liters of solution?
dj
Well, if I had a nickel for every time someone asked me about molarity, I'd have...well, probably not much money because I'm just a bot. But let's get to the point! To calculate molarity, you need to divide the number of moles of the solute by the volume of the solution in liters.
So, first, we need to find the number of moles of ammonia. To do that, we divide the mass of ammonia by its molar mass. The molar mass of ammonia is approximately 17.03 grams/mol. So, 14.1 grams of ammonia is roughly 0.826 moles.
Now, we divide the number of moles (0.826) by the volume of the solution in liters (0.100). Doing some quick math here, that gives us a molarity of 8.26 M.
So, the molarity of the solution would be around 8.26 M. Voila!
To find the molarity of the solution, we need to first calculate the number of moles of ammonia in 14.1 grams. The molar mass of ammonia (NH3) is 17.03 g/mol.
Step 1: Convert the mass of ammonia to moles.
Number of moles = mass / molar mass
= 14.1 g / 17.03 g/mol
= 0.827 moles (rounded to three decimal places)
Step 2: Calculate the molarity of the solution.
Molarity = moles / volume
= 0.827 moles / 0.100 L
= 8.27 M
Therefore, the molarity of the solution is 8.27 M.
To calculate the molarity of a solution, you need to know the number of moles of solute and the volume of the solution in liters.
Given:
Mass of ammonia (solute) = 14.1 grams
Volume of solution = 0.100 liters
To find the number of moles of ammonia, you need to use its molar mass and the mass given. The molar mass of ammonia (NH3) is 17.03 g/mol (nitrogen's molar mass = 14.01 g/mol and hydrogen's molar mass = 1.01 g/mol).
Number of moles of ammonia (NH3) = Mass of ammonia / Molar mass of ammonia
Substituting the values:
Number of moles of ammonia (NH3) = 14.1 g / 17.03 g/mol
Calculating this, you get:
Number of moles of ammonia (NH3) ≈ 0.826 mol
Now that you have the number of moles of ammonia (solute) and the volume of the solution, you can calculate the molarity using the formula:
Molarity (M) = Number of moles of solute / Volume of solution (in liters)
Substituting the values:
Molarity (M) = 0.826 mol / 0.100 L
Calculating this, you get:
Molarity (M) ≈ 8.26 M
Therefore, the molarity of the solution produced is approximately 8.26 M.
M=moles of solute/L of solution
Solute- ammonia NH3
Solvent- .1L H2O
Convert grams of NH3 to moles by dividing it by the molar mass. Then you plug that into the problem and solve.!