Posted by **Adam** on Tuesday, May 22, 2012 at 10:34pm.

A 0.700-kg ball is on the end of a rope that is 2.20 m in length. The ball and rope are attached to a pole and the entire apparatus, including the pole, rotates about the pole's symmetry axis. The rope makes an angle of 70.0° with respect to the vertical as shown. What is the tangential speed of the ball?

I got this:counterbalanced by the horizontal component of rope tension:

m*g*sin(70)

r=2.2*sin(70)

So here's the result

using g=9.81

v=sin(70)*sqrt(2.2*9.81)

v=4.36 m/s but its wrong could someone please help me out. Thank you.

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