Friday

August 22, 2014

August 22, 2014

Posted by **lilman** on Tuesday, May 22, 2012 at 7:04pm.

Can someone Please help I definitely do not know how to do this.

A)Find x, to find x you need to add the arc measures together and set the expression equal to the total degrees of circle then solve for X, must show all steps.

B)Is the triangle equilateral, isosceles, or scalene, explain, plug your x-value from A into each of the arc measures to find what each arc measures.

Apply the Inscribed Angles Theorem to find <P, <R, <S.

Use the angle measure from step 2 above to determine what type of triangle you have.

The picture is a circle with a triangle inside, QP=(8x-10) and PR=(6x), and QR=(10x+10) QP and PR are the sides and QR is the bottom.

Sure hope someone can help.

- circle inscribed -
**Reiny**, Tuesday, May 22, 2012 at 8:48pmAccording to the wording of part a) your description of

QP= 8x-10, PR = 6x etc

must have said

arc QP = 8x-10 etc

so 8x-10 + 6x + 10x+10 = 360

24x = 360

x = 15

so arc QP = 8(15) - 10 = 110°

PR = 90°

QR = 160°

By the inscribed angle theorem, the angle opposite the arc must be half the central angle subtended by the arc. Then....

angle R = 55°

angle Q =45°

angle P = 80°

looks like plain old**scalene**triangle

**Related Questions**

circles - a. To find X, you will need to add the arc measures together and set ...

circles and arcs - YOU have a circle with a traingle inside. P being the top of ...

geometry - m<S=30, m(arc)RS=84,and RU is tangent to the circle at R find m<...

geometry - Angle C is an inscribed angle of circle P. Angle C measures (-3x - 6...

GEOMETRY CIRCLE - 1.An isosceles triangle with each leg measuring 13 cm is ...

GEOMETRY CIRCLES PLEASE - HELP ME PLEASE. 1.An isosceles triangle with each leg...

geometry - In circle P, arc EN=66, angle GPM=89, and GN is the diameter. Find ...

Math rem - 2.Find the length of the arc in a circle if the radius of the circle ...

GEOMETRY CIRCLES PLEASE - 1.An isosceles triangle with each leg measuring 13 cm ...

maths - Im confused can any1 help me on this question ?? or try and put me on ...