algebra ll
posted by kim on .
600(x^2+x+1) using the formula b+/ sqrtb^4ac/2a

are you solving
600(x^2 + x + 1) = 0 ?
I will assume that, or else you have noting to solve.
divide each side by 600
x^2 + x + 1 = 0
x = (1 ± √3)/2
or (1 ± i√3)/2 , a pair of complex numbers.