Posted by Lily on Tuesday, May 22, 2012 at 8:40am.
Let's call propanoic acid HPr. Then
...........HPr ==> H^+ + Pr^-
Initial....3.0......0.....0
Change......-x......x......x
Equil.....3.0-x.....x.......x
Ka = (H^+)(Pr^-)/(HPr)
Substitute from the ICE chart into the Ka expression and solve for x = (H^+).
Then %ionization = [(H^+)/3.0)]*100 = ?
thank you so much!
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