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Posted by Lily on Tuesday, May 22, 2012 at 8:38am.

The PH of a 1.3M HF solution is 3.18. What % of the acid ionized?

pH = -log(H^+) 3.18 = -log(H^+) (H^+) = 6.6E-4 but you should confirm that. ...........HF ==> H^+ + F^- ...........1.3..6.6E-4..6.6E-4 %ionization = (6.6E-4/1.3)*100 = ?

thank you!!

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