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July 28, 2014

July 28, 2014

Posted by **Bob** on Tuesday, May 22, 2012 at 2:16am.

- Algebra 2 -
**Reiny**, Tuesday, May 22, 2012 at 8:05amfactor first

(3x-2)/((x-3)(x-9)) - (3x-8)/((x-3)(x-6)) + (x+2)/((x-9)(x-6))

so the LCD is ((x-3)(x-6)(x-9)

= [ (3x-2)(x-6) - (3x-8)(x-9) + (x+2)(x-3) ]/[(x-3)(x-6)(x-9)]

= [3x^2 - 20x + 12 - 3x^2 + 35x - 72 + x^2 - x - 6]/[(x-3)(x-6)(x-9)]

= (x^2 + 14x -66)/[(x-3)(x-6)(x-9)]

check my arithmetic

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