Tuesday

July 22, 2014

July 22, 2014

Posted by **ALISSA** on Tuesday, May 22, 2012 at 12:08am.

13)–2x^2 =

14)(-2x)^2 =

10)Use the discriminant to determine

the number of solutions of 3x^2-4x+6=0

8)Solve sqrt[3b] = -3

- math -
**Henry**, Thursday, May 24, 2012 at 4:33pm13. -2*(-3)^2 = -18.

14. (-2x)^2 = (-2*(-3)^2 = 6^2 = 36.

10. 3x^2 - 4x + 6 = 0.

D = sqrt(B^2-4AC).

D = sqrt(16-72) = sqrt(-56).

The Discriminant is < 0; therefore, we

have no real solutions and 2 imaginary

solutions.

8. sqrt(3b) = -3

Square both sides:

3b = 9

b = 3,

CHECK: sqrt(3*3) = sqrt(9)=+3,AND -3.

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