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July 29, 2014

July 29, 2014

Posted by **jennie cribzon** on Monday, May 21, 2012 at 9:28pm.

- maths -
**Jai**, Monday, May 21, 2012 at 10:11pmlet x = first number

let 8-x = second number

then we set up the equation. It says that the sum of their squares must be 34. thus,

x^2 + (8-x)^2 = 34

then we solve for x:

x^2 + 64 - 16x + x^2 = 34

2x^2 - 16x + 64 = 34

2x^2 - 16x + 30 = 0

x^2 - 8x + 15 = 0

since it's factorable, we can just factor this, and not use the quadratic formula:

(x-3)(x-5) = 0

x = 3 (first number)

8-x = 5 (second number)

if you get the x = 5, you will obtain same set of answers since 8-5 = 3.

hope this helps~ :)

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