Tuesday

September 2, 2014

September 2, 2014

Posted by **James** on Monday, May 21, 2012 at 3:40pm.

- Physics -
**James**, Monday, May 21, 2012 at 3:40pmYes, it's a super frog.

- Physics -
**Elena**, Monday, May 21, 2012 at 4:12pmThe time of jumping is

0.68•3600 = 2448 sec.

The distance covered by this small “projectile” (the frog) during 1 jump is

L =v²•sin2α/g.

We have Lmax => sin2α =1 and α = 45º.

Lmax= v² /g.

v =sqrt(Lmax•g) = sqrt(1.4•9.8) =3.7 m/s.

The time of 1 jump is

t = 2•v•sin α/g = 2•3.7•sin45º/9.8 =0.53 sec.

During the hour the frog made N jumps:

N = 2448/0.53=4619.

The total distance is

1.4•4619 =6467 m.

**Answer this Question**

**Related Questions**

physics - By trial and error, a frog learns that it can leap a maximum ...

pre-calc - path of a frogs leap: a frog leaps from a box 3 feet high and lands 4...

+1 SCIENCE PHYSICS - A FROG SAW AN INSECT ON THE GROUND AT A HORIZONTAL DISTANCE...

Math - Flights of leaping animals typically have parabolic paths. The figure ...

Physics - A frog is jumping around its pond. At some time t , the frog is in mid...

physical science - A frog jumps at the angle of 60 degrees to horizontal with ...

Math - To determine the question use Frogs F and G are 5cm to cube and 40cm to ...

Algebra - To determine the question use Frogs F and G are 5cm to cube and 40cm ...

Algebra - To determine the question use Frogs F and G are 5cm to cube and 40cm ...

Algebra - To determine the question use Frogs F and G are 5cm to cube and 40cm ...