Homework Help: Calculus I

Posted by Marissa on Monday, May 21, 2012 at 12:18pm.

Find the derivative of
y=ln((1+e^x)/(1-e^x))

I know that the derivative of y=ln(1+e^x) would be (e^x)/(1+e^x), but I'm not sure what to do with the 1-e^x on the bottom here. Can someone help please? Thanks!

Calculus I - Bosnian, Monday, May 21, 2012 at 12:50pm
In google type:
wolfram alpha

When you see lis of results click on:

Wolfram Alpha:Computational Knowledge Engine

When page be open in rectangle type:

derivartive ln((1+e^x)/(1-e^x))

and click option =

After few secons you will see result.

Then clic option Show steps
Calculus I - Reiny, Monday, May 21, 2012 at 1:35pm
first of all recall that
ln (A/B) = ln A - ln B
so
y = ln((1+e^x)/(1-e^x) )
= ln (1+e^x) - ln (1-e^x)
dy/dx = e^x/(1+e^x) - (-e^x)/(1 - e^x)

simplify as needed
Calculus I - Marissa, Tuesday, May 22, 2012 at 9:39am
Okay, thanks guys!

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