Find the derivative of
I know that the derivative of y=ln(1+e^x) would be (e^x)/(1+e^x), but I'm not sure what to do with the 1-e^x on the bottom here. Can someone help please? Thanks!
Calculus I - Bosnian, Monday, May 21, 2012 at 12:50pm
In google type:
When you see lis of results click on:
Wolfram Alpha:Computational Knowledge Engine
When page be open in rectangle type:
and click option =
After few secons you will see result.
Then clic option Show steps
Calculus I - Reiny, Monday, May 21, 2012 at 1:35pm
first of all recall that
ln (A/B) = ln A - ln B
y = ln((1+e^x)/(1-e^x) )
= ln (1+e^x) - ln (1-e^x)
dy/dx = e^x/(1+e^x) - (-e^x)/(1 - e^x)
simplify as needed
Calculus I - Marissa, Tuesday, May 22, 2012 at 9:39am
Okay, thanks guys!