Posted by Sam on Monday, May 21, 2012 at 9:27am.
suppressing the limit notation for the moment,
f' = [f(x+h)-f(x)]/h
f' = [(2(x+h)^2 + 5(x+h) + 2) - (2x^2 + 5x + 2)]/h
f' = [(2x^2 + 4xh + 2h^2) + (5x + 5h) + 2 - (2x^2 + 5x + 2)]/h
f' = (4xh + 2h^2 + 5h)/h
f' = 4x + 5 + 2h
lim as h->0 = 4x+5
-------------------------
f'(1) = 9
(y-5) = 9(x-1)
Thank you so so much! I finally understand what to do! :)
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