Posted by **Sam** on Monday, May 21, 2012 at 9:27am.

I am not sure what to do here:

Find the derivative (f '(x) using the limit process

a). f(x)= 2x^2+5x+2 find f ' (2)

b.) Find the equation of the Tangent Line at (1,5)

- Calculus -
**Steve**, Monday, May 21, 2012 at 10:21am
suppressing the limit notation for the moment,

f' = [f(x+h)-f(x)]/h

f' = [(2(x+h)^2 + 5(x+h) + 2) - (2x^2 + 5x + 2)]/h

f' = [(2x^2 + 4xh + 2h^2) + (5x + 5h) + 2 - (2x^2 + 5x + 2)]/h

f' = (4xh + 2h^2 + 5h)/h

f' = 4x + 5 + 2h

lim as h->0 = 4x+5

-------------------------

f'(1) = 9

(y-5) = 9(x-1)

- Calculus -
**Sam**, Monday, May 21, 2012 at 10:43am
Thank you so so much! I finally understand what to do! :)

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