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October 2, 2014

October 2, 2014

Posted by **Rachel** on Sunday, May 20, 2012 at 11:41pm.

- Geometry -
**Steve**, Monday, May 21, 2012 at 12:27amthe center of the circle will be at the intersection of the perpendicular bisectors of two of the line segments joining the points. If we label the points

A:(1,3)

B:(5,11)

C:(11,4)

then we have

AB: midpoint=(3,7) slope=2

BC: midpoint=(8,15/2) slope=-7/6

CA: midpoint=(6,7/2) slope=1/10

so, the equations of the perpendicular bisectors are

AB: y = 1/2 (17-x)

AC: y = 3/14 (4x+3)

CA: y = 1/2 (127-20x)

These all intersect at (220/38,213/38)

The radius of the circle is 5√1717/38

(x-220/38)^2 + (y-213/38)^2 = 42925/1444 = 29.726

Ouch! Hard to believe, but the math checks out.

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