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September 21, 2014

September 21, 2014

Posted by **:)** on Sunday, May 20, 2012 at 9:02pm.

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**:)**, Sunday, May 20, 2012 at 9:03pmi'm sorry, this is about optimization problems.

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**Damon**, Sunday, May 20, 2012 at 9:34pmx and (10 - x)

x is 2 pi r

r = x/(2 pi)

Ac = pi r^2 = pi x^2/(4pi^2) = x^2/(4pi)

(10 -x) = 4*side = 4 s

so

s = (10-x)/4

As = s^2 = (100-20 x + x^2)/16

A= Ac+As = x^2/4pi + (1/16)(x^2-20x+100)

dA/dx = 0 for max or min

0= x/2pi +1/16 (2x-20)

0= .16 x + .125 x - 1.25

0= .285 x - 1.25

x = 4.4

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