Homework Help: related rates

Posted by :) on Sunday, May 20, 2012 at 9:01pm.

After blast-off, a space shuttle climbs vertically and a radar-tracking dish, located 1000 meters from the launch pad, follows the shuttle. How fast is the radar dish revolving 10 sec after blast-off if at that time the velocity of the shuttle is 100 m/sec and the shuttle is 500 meters above the ground?

related rates - Damon, Sunday, May 20, 2012 at 9:23pm
h = height = 500 + 100 t
b = base = 1000
A = elevation angle. we want dA/dt

tan A = h/b = 100(5+t) / 1000 = .5 +.1 t

(1 /sec^2 A) dA/dt = 0 + .1

dA/dt = .1 sec^2 A

at this time ratio of b to h is 2/1
so hypotenuse is sqrt 5
cos A = 2/sqrt 5
sec A = sqrt 5/2
sec^2 A = 5/4
so
dA/dt = .1 (5.4) = .54 radians/second
or
31 degrees per second
sec A = 1/cos A = 1/(1000/(1000^2

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