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September 19, 2014

September 19, 2014

Posted by **:)** on Sunday, May 20, 2012 at 9:01pm.

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**Damon**, Sunday, May 20, 2012 at 9:23pmh = height = 500 + 100 t

b = base = 1000

A = elevation angle. we want dA/dt

tan A = h/b = 100(5+t) / 1000 = .5 +.1 t

(1 /sec^2 A) dA/dt = 0 + .1

dA/dt = .1 sec^2 A

at this time ratio of b to h is 2/1

so hypotenuse is sqrt 5

cos A = 2/sqrt 5

sec A = sqrt 5/2

sec^2 A = 5/4

so

dA/dt = .1 (5.4) = .54 radians/second

or

31 degrees per second

sec A = 1/cos A = 1/(1000/(1000^2

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