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September 2, 2014

September 2, 2014

Posted by **chels** on Sunday, May 20, 2012 at 6:54pm.

- Algebra 2 -
**Damon**, Sunday, May 20, 2012 at 8:57pmx = Xi e^-kt

x/Xi = .5 = e^-5730 k

ln .5 = -5730 k

-.69315 = -5730 k

k = 1.21*10^-4

x = Xi e^-1.21*10^-4 t

2 = 50 e^-1.21*10^-4 t

.04 = e^-1.21*10^-4 t

ln .04 = -1.21*10^-4 t

-3.22 = -1.21*10^-4 t

2.66 * 10^4

= 26,600 years

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