Posted by Dav e on Sunday, May 20, 2012 at 5:01pm.
I'll try to explain the schmatic drawing...
a 120V battery, total of 12A, leads into a 8ohm resistor (R1), then breaks off into two parallel lines, R2 and R3. the resistance is unknown in R2, and in R3 the resistance is 3 ohms. I need to find the Amperage in R1,R2 and R3 as well as the resistance (ohms) on R2
I hope this explains it... HELP

physicsseries and parellel circuits  Dav e, Sunday, May 20, 2012 at 5:02pm
OOOPA and the voltage at R1, R2 and R3

typo?  Damon, Sunday, May 20, 2012 at 5:11pm
12 amps through R1
volts across R1 = 8*12 = 72
That leaves 120  72 = 48 volts across R2 and R3
amps through R3 = 48/3 = 16 amps
You have a typo I think. Perhaps R3 is 30 and not 3 ohms?

physicsseries and parellel circuits  Dav e, Sunday, May 20, 2012 at 5:38pm
R3 is 3 ohms

physicsseries and parellel circuits  Damon, Sunday, May 20, 2012 at 5:49pm
Well, you have set up a physically impossible situation where R2 would have to be negative. You can not have 12 amps coming out of the battery and 16 amps through R3. Please check your problem statement carefully. Maybe you have 1.2 amps out of the battery?

physicsseries and parellel circuits  Dav e, Sunday, May 20, 2012 at 5:50pm
For R1 voltage .. E=I*R
E=8*12=96 volts correct?

physicsseries and parellel circuits  Damon, Sunday, May 20, 2012 at 5:58pm
whoops, right. I multiplied wrong

physicsseries and parellel circuits  Damon, Sunday, May 20, 2012 at 6:00pm
120  96 = 24 volts across R2 and R3
current through R3 = 24/3 = 8 amps
then 4 amps through R2
R2 = 24/4 = 6 ohms
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