Posted by **Brandon** on Sunday, May 20, 2012 at 4:36pm.

The minute hand of a bedside clock is 2.5 cm long. In order for the clock to keep proper

time, the minute hand should maintain an average angular velocity of

- physics? -
**bobpursley**, Sunday, May 20, 2012 at 4:39pm
IT makes one round (2PI radians) per hour,

speed= 2PIrad/hr*1hr/3600sec*2.5cm or

speed= 0.00436332313 cm/second

- physics? -
**drwls**, Sunday, May 20, 2012 at 7:01pm
They ask for an angular velocity. That would be independent of the minute hand's length, and would be (2*pi rad/h)/(3600 sec/h) = 1.745*10^-3 rad/s

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