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March 26, 2017

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2.The distance travelled by a body moving with uniform acceleration in the nth second is given by Sn=3.8+0.4n,find the velocity of the body

  • physics - ,

    Sn=3.8+0.4-----(eqn 1)
    Sn=u+a(n-1/2)
    =u+an-a/2
    Sn=(u-a/2)+an------(eqn 2)
    from 1 and 2
    a=0.4m/s^2
    u-a/2=3.8
    u-0.4/2=3.8
    u-0.2=3.8
    u=6.0m/s

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