physics
posted by srikar on .
2.The distance travelled by a body moving with uniform acceleration in the nth second is given by Sn=3.8+0.4n,find the velocity of the body

Sn=3.8+0.4(eqn 1)
Sn=u+a(n1/2)
=u+ana/2
Sn=(ua/2)+an(eqn 2)
from 1 and 2
a=0.4m/s^2
ua/2=3.8
u0.4/2=3.8
u0.2=3.8
u=6.0m/s