physics
posted by Martin on .
given that the mass of an electron is 9.1 x 10^28 grams and the charge on an electron is 1.6 x 10^19 Coulombs, calculate the voltage required to lift an electron 5 cm.
the question was previously answered, but I did'nt understand it .. could some show me again please.

Weight x Distance = (charge)*(Voltage difference)
M*g*X = e*V
Solve for V
e = 1.6*10^19 C
g = 9.8 m/s^2 (on Earth)
X = 0.05 m
M = 9.1*10^31 kg
V = 2.8*10^12 volts