Post a New Question


posted by .

given that the mass of an electron is 9.1 x 10^-28 grams and the charge on an electron is 1.6 x 10^-19 Coulombs, calculate the voltage required to lift an electron 5 cm.

the question was previously answered, but I did'nt understand it .. could some show me again please.

  • physics -

    Weight x Distance = (charge)*(Voltage difference)

    M*g*X = e*V

    Solve for V
    e = 1.6*10^-19 C
    g = 9.8 m/s^2 (on Earth)
    X = 0.05 m
    M = 9.1*10^-31 kg

    V = 2.8*10^-12 volts

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question