Homework Help: physics

Posted by Martin on Saturday, May 19, 2012 at 8:20pm.

given that the mass of an electron is 9.1 x 10^-28 grams and the charge on an electron is 1.6 x 10^-19 Coulombs, calculate the voltage required to lift an electron 5 cm.

the question was previously answered, but I did'nt understand it .. could some show me again please.

physics - drwls, Saturday, May 19, 2012 at 11:19pm
Weight x Distance = (charge)*(Voltage difference)

M*g*X = e*V

Solve for V
e = 1.6*10^-19 C
g = 9.8 m/s^2 (on Earth)
X = 0.05 m
M = 9.1*10^-31 kg

V = 2.8*10^-12 volts

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