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A 5.0 µC point charge is moved within an electric field and has an electric potential energy change of 10.0 J. What is the electric potential difference before and after the charge was moved? Show work. (µC = 1.0 × 10–6

so delta V must be 10 volts.
What do I do NOW?

  • Physics - ,

    You mean V * q = energy
    V = energy / q

    The potential difference * charge = potential energy change of charge

    delta V = 10J/(5*10^-6) = 2*10^6 volts

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