Posted by **Jennifer** on Saturday, May 19, 2012 at 11:48am.

An electron ( mass = 9.11×10−31 kg) leaves one end of a TV picture tube with zero initial speed and travels in a straight line to the accelerating grid, which is 1.85 cm away. It reaches the grid with a speed of 2.95×10^6 m/s . (You can ignore the gravitational force on the electron.)

If the accelerating force is constant, compute the acceleration of the electron. If the accelerating force is constant, compute the time it takes the electron to reach the grid. If the accelerating force is constant, compute the net force that is accelerating the electron, in newtons.

## Answer This Question

## Related Questions

- Physics - An electron (m = 9 x 10-31 kg) leaves the cathode of a radio tube with...
- Physics - An electron of mass 9.11 10-31 kg has an initial speed of 2.60 105 m/s...
- physics - An electron of mass 9.11 10-31 kg has an initial speed of 3.00 105 m/s...
- csub - an electron of mass 9.11*10^-31 kg has an initial speed of 4.00*10^5 m/s...
- physics - what kinetic energy does an electron acquire if it falls through a ...
- physics - An electron of mass 9.11 10-31 kg has an initial speed of 2.85 105 m/s...
- College Physics - An electron in a television tube travels the 12 cm distance ...
- Physics (Kinematics) - In a television tube, the electron travels from an ...
- Physics - The electrons that produce the picture in a TV set are accelerated by ...
- college physics - The electrons that produce the picture in a TV set are ...

More Related Questions