Posted by **Anonymous** on Saturday, May 19, 2012 at 10:56am.

a satellite completes one revolution of a planet in almost exactly one hour. at the end of an hour , the satellite has traveled 2.0x10^7 meters and is only 10 meters away from its starting point. What is the numerical value of the satellite's average velocity after that one hour?

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**drwls**, Saturday, May 19, 2012 at 11:55am
The trick here is to recognize that they are asking for average velocity, not speed. In exactly one hour, it is only 10 meters from where is was 3600 seconds ago. Compute the ratio, 10 m/3600 s

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**Henry**, Saturday, May 19, 2012 at 8:30pm
post it.

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**hello**, Monday, June 11, 2012 at 3:24pm
A satellite completes one revolution of a planet in almost exactly one hour. At the end of one hour, the satellite has traveled 2.0 × 107 meters and is only 10 meters away from its starting point. What is the numerical value of the satellite's average velocity after that one hour?

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**adam**, Friday, May 31, 2013 at 1:03pm
a satellite completes one revolution of a planet in almost exactly one hour. at the end of an hour , the satellite has traveled 2.0x10^7 meters and is only 10 meters away from its starting point. What is the numerical value of the satellite's average velocity after that one hour?

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