Posted by **eve** on Saturday, May 19, 2012 at 9:14am.

Hello. Please, help me solve this:

Parabola y = ax^2 + bx + c passes through the point (2;-6). Find the values of a, b and c, if vertex of parabola is (4;-10).

- math -
**Reiny**, Saturday, May 19, 2012 at 10:07am
let's find the equation in its standard form using the given information

since the vertex is (4,-10)

it must be

y = a(x-4)^2 -10

but (2,-6) lies on it

-6 = a(-2)^2 - 10

4 = 4a

a = 1

so y = (x-4)^2 - 10

y = x^2 - 8x + 16 - 10

y = x^2 - 8x + 6

so a=1, b=-8 and c=6

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