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November 28, 2014

November 28, 2014

Posted by **srikar** on Saturday, May 19, 2012 at 2:23am.

2.A runner travels 1.5 laps around a circular track of 50sec .The diameter of the track is 40m and its circumferenceis 126m.Find a)average speed of the runner and b)the magnitude of the runner average velociy

- physics -
**drwls**, Saturday, May 19, 2012 at 6:44amSomeone will gladly critique your thinking, when any is shown.

- physics -
**Elena**, Saturday, May 19, 2012 at 5:11pm1.

s =vₒ•t +a•t²/2,

v(9) = vₒ +a•9,

24 =v(9) •1 + a•1²/2 =

=vₒ +a•9 + a•1²/2 =

= vₒ +9.5•a.

s =vₒ•t +a•t²/2 =>

150 = vₒ•10+ a•100/2 =

= 10• vₒ + 50•a.

24= vₒ +9.5•a,

150= 10• vₒ + 50•a.

45° = 90,

a = 2 m/s².

vₒ = 24-9.5 •a = 5 m/s.

2.

Average speed = total distance travelled/ total time taken = 1.5•126/50 = 3.78 m/s,

Displacement is the distance from the starting point to the end point.

Average velocity = final displacement/total time taken = D/t = =40/50 =0.8 m/s.

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