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April 18, 2014

Posted by **srikar** on Saturday, May 19, 2012 at 1:32am.

2.The distance travelled by a body moving with uniform acceleration in the nth second is given by Sn=3.8+0.4n,find the velocity of the body .

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**Elena**, Saturday, May 19, 2012 at 5:51pm1.

vₒ = 18 km/hr = 18000/3600 = 5 m/s.

a = 9 cm/s² = 0.09 m/s².

s =(v² - vₒ²)/2•a.

v = sqrt (vₒ² +2•a•s) = sqrt(25 +2•0.09•200) =7.81 m/s.

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**Elena**, Saturday, May 19, 2012 at 6:02pm2.

Distance traveled by a body in nth second is

Sn = u + (2n-1)•a/2.

If you know acceleration "a" you can find velocity "u"

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**Henry**, Saturday, May 19, 2012 at 7:20pmVo = 18km/h =18000m/3600s=5m/s=Initial

velocity.

1a. a =9cm/s^2 * 0.01m/cm = 0.09 m/s^2.

1b. V^2 = Vo^2 + 2ad

V^2 = 5^2 ++ 0.18*200 = 61

V = 7.81 m/s. = Final velocity.

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**saila**, Sunday, May 20, 2012 at 1:49amwhat is "sqrt" please can i know?????

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**Elena**, Sunday, May 20, 2012 at 4:54amsqrt=square root=quadratic root=second root

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