An electric drill operates at a potential difference of 120V and draws a current of 1.5 Amps. If it takes 50 seconds to drill a hole in a piece of steel,calculate the amount of electrical energy used by the drill in that time.
And the phase angle (power factor) is what?
I assume your teacher wants you to ignore that power drills are not inductive.
With that imagination,
power= energy/time
energy= power*time= VI*time=120*1.5*50 joules
Hi bob, could you explain how you came to that calculation, please.
As in where did the 1.5 come from, and the 50 joules(it was 50 seconds) I'm lost, could you help?
Thanks
energyinJoules=powerinwatts*timeinSeconds
= Voltageinvolts*CurrentinAmps*timeinSeconds
Ahhh so its 120*7.5*50seconds
7.5 being the amps that the drill draws and 50 being the time and 120 being the voltage.
To calculate the electrical energy used by the drill, we need to use the formula:
Energy (E) = Power (P) × Time (t)
First, let's calculate the power used by the drill:
Power (P) = Potential Difference (V) × Current (I)
Given:
Potential Difference (V) = 120V
Current (I) = 1.5 Amps
P = V × I
P = 120V × 1.5 Amps
P = 180 Watts
Now that we have calculated the power used by the drill, we can calculate the electrical energy used using the formula:
E = P × t
Given:
Time (t) = 50 seconds
E = 180 Watts × 50 seconds
E = 9000 Joules
Therefore, the electric drill uses 9000 Joules of electrical energy to drill a hole in 50 seconds.