Posted by Kira on Friday, May 18, 2012 at 3:54pm.
I am not certain if the 20pi x^2 is in the denominator or not of the first term. If it is really this,
f(x)=[1/(x(27,000,000/pi + 6,750,000)] + 20PI x^2
then work it in two parts, the first, and second term.
f(x)=1/kx + 20 pi x^2
f'= -1/kx^2 + 40PI x
where k= 27E6/PI +6.75E6
Here I'll write it again but distribute the 1/x so you can see it better.
f(x) = (27,000,000/pix)+(6,750,000/x)+20pix^2
Does that help?
The 1/x was only factored out of the first two terms, not out of the
20pi(x^2)
But I get the general idea. I just write 1/x as x^-1 and differentiate that. Makes sense, thanks!
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