Posted by James on Friday, May 18, 2012 at 1:08pm.
total energy at beginning=totalenergy at point above
1/2 m vi^2=1/2 m 5^2+mg(3/4 h)
this indicates that you have two variables, height, and velocity initially.
but we know in the final 1/4 h, vf=0, and
Vf^2=Vi^2+2gd
0=25-2*9.8*h/4
or h=50/9.8
now you can solve for vi in the first equation.
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