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March 28, 2017

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A runner of mass 51.5 kg starts from rest and accelerates with a constant acceleration of 1.35 m/s2 until she reaches a velocity of 5.7 m/s. She then continues running with this constant velocity. (Take the direction the runner is going to be the positive direction. Indicate the direction with the sign of your answer.)

  • Physics - no question - ,

    can't give an answer with no question. All you have done is present some data.

  • Physics - ,

    Oh, sorry I forgot to post the rest of the question.

    (a) How far has she run after 64.7 s?

    (b) What is the velocity of the runner at this point?

  • Physics - ,

    v= a •t,
    t=v/a =5.7/1.35 = 4.2 s.
    The distance covered for this time is
    s1 = a •t²/2 = 1.35 •(4.22)²/2 =12 m.

    If 64.7 is the total time of the motion, then the time
    of uniform motion is
    t1= 64.7 -4.2 =60.5 s.
    The distance for this time is
    s2 = v •t1 = 5.7 •60.5 =344.9 m.
    The total distance is s1+s2 = 12 +344.9 = 356.9 m.

    If 64.7 sec. is the time of uniform motion, then
    s2 = 5.7 •64.7 =368.8 m.
    Therefore, the total distance is
    368.8 + 12 =380.8 m.
    The velocity at this point is 5.7 m/s as she runs at a constant speed.

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