Records from buzz's sawmill show that workers have a 0.02 probability of losing an arm and a 0.03 probability of losing a leg in a year.

What is the probability that a worker does not lose an arm?

What is the probability that worker does not lose and arm or leg?

Pr(NOT arm)=.98

Pr(NOT arm NOR leg)= 1-Pr(leg)-pr(arm)

oops.

Pr(NOT arm NOR leg)=1-Pr(arm or leg)
= 1-Pr(arm)-Pr(leg)+pr(arm AND leg)
= 1-.02-.03+.02*.03

To find the probability that a worker does not lose an arm in a year, we can subtract the probability of losing an arm from 1.

Probability of not losing an arm = 1 - Probability of losing an arm

Given that the probability of losing an arm is 0.02, the probability of not losing an arm would be:

Probability of not losing an arm = 1 - 0.02 = 0.98

So, the probability that a worker does not lose an arm is 0.98.

To find the probability that a worker does not lose an arm or leg, we can subtract the probability of losing an arm and the probability of losing a leg from 1.

Probability of not losing an arm or leg = 1 - Probability of losing an arm - Probability of losing a leg

Given that the probability of losing an arm is 0.02 and the probability of losing a leg is 0.03, the probability of not losing an arm or leg would be:

Probability of not losing an arm or leg = 1 - 0.02 - 0.03 = 0.95

So, the probability that a worker does not lose an arm or leg is 0.95.