Saturday

April 19, 2014

April 19, 2014

Posted by **Anonymous** on Friday, May 18, 2012 at 6:07am.

The sign hangs from a light, rigid horizontal support of length 0.48m that is hinged to the wall at one end A. The other end B of the support is attached by a model string to a point C at a distance 0.2m vertically above the point A. You may model the sign as a particle located below the midpoint of the horizontal support AB.

By taking torques abut the hinged end A, and considering equilibrium of the beam, find the tension in the rope.

- Physics -
**bobpursley**, Friday, May 18, 2012 at 9:00ama. label the forces at the supports, and the hanging end.

Here it is in my head:

the angle at the rope to horizontal is Theta. W is the weight of the sign. T is tension.

Torque about A:

Tension*Lengthstring*cosTheta-Weight=0

but cosTheta= .48/lengthstring

**Related Questions**

physics - A .1kg mass is located on the line between a 5kg mass and a 10kg mass...

physics - what is the centripetal force acting on an object with a mass of 10kg ...

Math - Students in Mr. Tandoc's shop class made a circular railroad crossing ...

Math - Students in Mr.Tandoc's shop class made a circular railroad crossing sign...

Physics - Cart A (mass 10kg) and cart B (mass= 10kg) are connected by a ...

physics - A mass of 10kg is placed on the top of a plane inclined at 45 degrees ...

physics - what is thw momentum of an object of mass 10Kg at rest?

physics - A man of mass 70kg carries a mass of 10kg to the top of a building ...

physics - A mass of 10kg moves with a velocity of 4m/s. What is its kinetic ...

Phys. - Cart A (mass 10kg) and cart B (mass= 10kg) are connected by a compressed...