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March 3, 2015

March 3, 2015

Posted by **Anonymous** on Friday, May 18, 2012 at 6:07am.

The sign hangs from a light, rigid horizontal support of length 0.48m that is hinged to the wall at one end A. The other end B of the support is attached by a model string to a point C at a distance 0.2m vertically above the point A. You may model the sign as a particle located below the midpoint of the horizontal support AB.

By taking torques abut the hinged end A, and considering equilibrium of the beam, find the tension in the rope.

- Physics -
**bobpursley**, Friday, May 18, 2012 at 9:00ama. label the forces at the supports, and the hanging end.

Here it is in my head:

the angle at the rope to horizontal is Theta. W is the weight of the sign. T is tension.

Torque about A:

Tension*Lengthstring*cosTheta-Weight=0

but cosTheta= .48/lengthstring

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