Posted by Bluesky on Thursday, May 17, 2012 at 7:34pm.
for y-intercept , let x = 0
so y = 0+0-5 = -5
y-intercept is -5
for x-intercept , let y = 0
x^2 + 4x - 5 = 0
(x+5)(x-1) = 0
x = -5 or x = 1
the x-intercepts are -5 and 1
for vertex , complete the square
y = x^2 + 4x + 4 - 4- 5
= (x+2)^2 - 9
vertex is (-2,-9)
axis of symmetry: x = -2
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