Posted by **Bluesky** on Thursday, May 17, 2012 at 7:34pm.

y= x^2 +4x-5

x intercept- 4?

y intercept- -5?

vertex-? I don't know how to find the vertex.

axis of symmetry?

- Math does anyone know this? -
**Reiny**, Thursday, May 17, 2012 at 8:13pm
for y-intercept , let x = 0

so y = 0+0-5 = -5

y-intercept is -5

for x-intercept , let y = 0

x^2 + 4x - 5 = 0

(x+5)(x-1) = 0

x = -5 or x = 1

the x-intercepts are -5 and 1

for vertex , complete the square

y = x^2 + 4x + 4 - 4- 5

= (x+2)^2 - 9

vertex is (-2,-9)

axis of symmetry: x = -2

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