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Posted by on Thursday, May 17, 2012 at 7:34pm.

y= x^2 +4x-5

x intercept- 4?
y intercept- -5?
vertex-? I don't know how to find the vertex.
axis of symmetry?

  • Math does anyone know this? - , Thursday, May 17, 2012 at 8:13pm

    for y-intercept , let x = 0
    so y = 0+0-5 = -5
    y-intercept is -5

    for x-intercept , let y = 0
    x^2 + 4x - 5 = 0
    (x+5)(x-1) = 0
    x = -5 or x = 1
    the x-intercepts are -5 and 1

    for vertex , complete the square
    y = x^2 + 4x + 4 - 4- 5
    = (x+2)^2 - 9
    vertex is (-2,-9)

    axis of symmetry: x = -2

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