Math does anyone know this?
posted by Bluesky .
y= x^2 +4x5
x intercept 4?
y intercept 5?
vertex? I don't know how to find the vertex.
axis of symmetry?

for yintercept , let x = 0
so y = 0+05 = 5
yintercept is 5
for xintercept , let y = 0
x^2 + 4x  5 = 0
(x+5)(x1) = 0
x = 5 or x = 1
the xintercepts are 5 and 1
for vertex , complete the square
y = x^2 + 4x + 4  4 5
= (x+2)^2  9
vertex is (2,9)
axis of symmetry: x = 2