Posted by **jenika** on Thursday, May 17, 2012 at 7:03pm.

y=2x-1

2x-y-1=0

a)this sytem has excatly onw solution

b)this system has indinetly many solutions

c)this system has no solution

d)(1,1) and (0,0)

- algebra 1 -
**Reiny**, Thursday, May 17, 2012 at 7:08pm
mmmmhhh?

Isn't the second equation the same as the first?

And how many points would satisfy the first?

So what do you think?

- algebra 1 -
**jenika**, Thursday, May 17, 2012 at 7:10pm
ohhhh so just one solution right?

- algebra 1 -
**Rezu**, Thursday, May 17, 2012 at 7:36pm
If you mean infinite not indinetly than the answer is C.

2x-y-1=0 subtract 2x from each side

-y-1 = -2x + 0 add 1 to each side

-y = -2x + 1 multiply everything by -1

y = 2x-1

The equations are equal, so the system has infinite solutions.

- algebra 1 -
**jenika**, Thursday, May 17, 2012 at 7:55pm
oh ok thanks alot

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