Saturday

April 19, 2014

April 19, 2014

Posted by **Liz** on Thursday, May 17, 2012 at 12:34pm.

There are 12 red checkers and 3 black checkers in a bag. Checkers are selected one at a time, with replacement. Each time, the color of the checker is recorded. Find the probability of selecting a red checker exactly 7 times in 10 selections. Show your work.

Answer:

P(success)=P(red)= 12/15= 0.8

n=7 r=5

10C7= 10!/(10-7)! = 10!/3! = 10*9*8*7*6*5*4*3!/ 3!= 10*9*8*7*6*5*4= 604,800

P(red7times)= 10C7 (0.8)^7(0.2)^3

= 604,800 (0.8)^7(0.2)^3

= 604,800 (0.2)(.008)

= 604,800(0.0016)

=967.68

- Algebra2 {ASAP} -
**PsyDAG**, Friday, May 18, 2012 at 2:45pmHow can the probability be greater than one?

The probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

(12/15)^7 * (3/15)^3 = ?

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