Posted by **Liz** on Thursday, May 17, 2012 at 12:34pm.

Hi helper, I used permutation for the following question. How can i use combination to find the answer? Help me please!

There are 12 red checkers and 3 black checkers in a bag. Checkers are selected one at a time, with replacement. Each time, the color of the checker is recorded. Find the probability of selecting a red checker exactly 7 times in 10 selections. Show your work.

Answer:

P(success)=P(red)= 12/15= 0.8

n=7 r=5

10C7= 10!/(10-7)! = 10!/3! = 10*9*8*7*6*5*4*3!/ 3!= 10*9*8*7*6*5*4= 604,800

P(red7times)= 10C7 (0.8)^7(0.2)^3

= 604,800 (0.8)^7(0.2)^3

= 604,800 (0.2)(.008)

= 604,800(0.0016)

=967.68

## Answer this Question

## Related Questions

- Algebra II - Help me with this question please There are 12 red checkers and 3 ...
- math - in each game there are 12 red checkers and 12 black checkers.If tom put ...
- math - a bag contains 12 black checkers and 12 red checkers. What is the ...
- Algebra ll - Help me with this please There are 12 red checkers and 3 black ...
- Algebra II - help please There are 12 red checkers and 3 black checkers in a bag...
- Algebra - 3. There are 12 red checkers and 3 black checkers in a bag. Checkers ...
- Math - If I picked a red checker from a bag of 9 black checkers and 6 red ...
- math - What is the probability of drawing a red checker from a bag of 9 black ...
- math - drawing a black checker from a bag of 9 black checkers and 6 red checkers...
- math - A bag contains 7 red checkers and 11 black checkers. One checker is drawn...

More Related Questions