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Chemistry

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How many grams of CO are needed to react with an excess of Fe2O3 to produce 209.7gFe? Fe2O3(s) + 3CO(g) => 3CO2(g) + 2Fe(s)

  • Chemistry -

    Convert 209.7 g Fe to mols. molsl = grams/molar mass
    Using the coefficients in the balanced equation, convert mols Fe to mols CO.
    Now convert mols CO to grams. g = mols x molar mass.

  • Chemistry -

    Moles Fe = 209.7 g / 55.847 = 3.75
    the ratio between CO and Fe is 3 : 2
    Moles CO needed = 3.75 x 3 / 2 = 5.63
    Mass CO = 5.63 mol x 28.01 g/mol =157.7 g

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