1) Period is inversely proportional to g. On the moon, g is 9.8/6 = 1.63 m/s^2.
Pendulum period is 6s*sqrt6 = 14.7 s.
2) Solve P = 6.28 s = 6.28 sqrt(L/g)
L/g = 1 s^2
L = 9.8 m
3) Wavelength = (Wave speed)/(frequency)
= (40 m/s)/10 s^1) = 4 m
T =6 s. g = 9.8 m/s², T2=?
Acceleration due to gravity at the Moon is
g1 = G•M1R1²,
where the gravitational constant G =6.67•10^-11 N•m²/kg²,
Mass of the moon M1= 7.36•10^22 kg,
Radius of the Moon R1 = 1.74 •10^6 m.
T1 = 2•π•sqrt(L/g1).
T1 = T/sqrt(g1/g),
2. T=6.28 s. L=?
L = (T/2•π)² •g
λ = v/f =40/10 = 4 m
x = λ/2 = 2 m
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