posted by Joel on .
How do I calculate the mass of sodium carbonate required to neutralize 15-20 mL
of 0.25M HCl at the stoichiometric point?
Na2CO2 + 2HCl ==> 2NaCl + CO2 + H2O
Say 20 mL. How many mols is that? M x L = mols HCl.
mols Na2CO3 = 1/2 that.
g Na2CO3 = mols x molar mass.