What are the vertical and horizontal asymptotes of y=(4/x-3)+2
Vertical asymptote is where the denominator of a rational function becomes zero.
Assuming you made a typo and that you really mean:
y = 4/(x-3) + 2
then the denominator becomes zero at x=3.
The horizontal asymptote is what y becomes as x-> -∞ or x->+∞.
Can you figure out the second part?